Solve this:
10.6 g of a substance of molecular weight 106 was dissolved in 100 ml. 10 ml of this solution was pipetted out into a 1000 ml flask and made up to the mark with distilled water. The molarity of the resulting solution is
1) 1 M         2) 10-2 M
3) 10-3         4) 10-4 M

Dear Student,


Initial Molarity of the solution,M1= MassMolar mass×1000Volume of solution                                                  =10.6106×1000100                                                  =1 MUsing dilution formula, M1V1=M2V2M1= 1MV1 = 10 mlV2=1000 mlSo,M2=M1V1V2            =1×101000            =10-2 MHence, correct answer is (2)

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