Solve this: 11 If two molecules of A and B having mass 121 Kg and 81 Kg and - Chemistry - Chemical Kinetics

Question

Solve this:

11 If two molecules of A and B having mass 121 Kg
and 81 Kg and rate of diffusion of A is 16   ×   10
- 3 , then what will be the rate of diffusion of B?

a   20 75   ×   10 - 3 b   20 75  
×   10 - 4 c   19 75   ×   10 - 3 d
  20 75   ×   10 - 4

Megha Sharma · Accepted Answer

Dear student,
According to Graham's Law of Diffusion,
(rA/ rB) = (
MB / MA )1/2
(16 * 10 -3 / rB ) = ( 81 / 121 )
1/2

( 16 * 10 -3 / rB ) = ( 9 / 11 )
rB = 16 *11 * 10-3 / 9
rB = 19 55 * 10 -3
The answer is (c)
Regards

Solve this: 11. If two molecules of A and B having mass 121 Kg and 81 Kg and rate of diffusion of A is 16 × 10 - 3 , then what will be the rate of diffusion of B? a 20 . 75 × 10 - 3 b 20 . 75 × 10 - 4 c 19 . 75 × 10 - 3 d 20 . 75 × 10 - 4

Solve this:

11. If two molecules of A and B having mass 121 Kg and 81 Kg and rate of diffusion of A is $16 \times 10^{- 3}$ , then what will be the rate of diffusion of B?

$(a) 20.75 \times 10^{- 3} (b) 20.75 \times 10^{- 4} (c) 19.75 \times 10^{- 3} (d) 20.75 \times 10^{- 4}$