Solve this : 23 The vapour pressure of pure benzene at 298 K is 97 0 mm Hg - Chemistry - Solutions

Question

Solve this :

23 The vapour pressure of pure benzene at 298 K is 97 0 mm Hg The
vapour pressure of solution containing 10 0 g of naphthalene (mol
wt 128) in 100 g of benzene at 398 K will be
A 79 5 mm Hg B 91 43 mm Hg
C 81 45 mm Hg D 66 5 mm Hg

Akansha Chauhan · Accepted Answer

Dear Student,

Please find the answer to your question

According to Rault’s law,

Po-­P/Po = w/m /w/m +W/M

Here, Po = 97 mm
p = ?
W =
10 g W = 100
M =
? M = 78

Substituting the various values in the above equation for
Roult’slaw :
97
-p/97 = 10/m /2 175/m+39/78

1/16 = 2 175/2 175 + 0 5 m
m =
65 25

Solve this.: 23. The vapour pressure of pure benzene at 298 K is 97.0 mm Hg. The vapour pressure of solution containing 10.0 g of naphthalene (mol. wt. 128) in 100 g of benzene at 398 K will be. A. 79.5 mm Hg. B. 91.43 mm Hg C. 81.45 mm Hg. D. 66.5 mm Hg.

Solve this.:

23. The vapour pressure of pure benzene at 298 K is 97.0 mm Hg. The vapour pressure of solution containing 10.0 g of naphthalene (mol. wt. 128) in 100 g of benzene at 398 K will be.
A. 79.5 mm Hg. B. 91.43 mm Hg
C. 81.45 mm Hg. D. 66.5 mm Hg.