Solve this:
35. The emf of a galvanic cell constituted with the electrodes is
(1) -0.35 V (2) +1.17 V
(3) +0.35V (4) -1.17 V
Zn is more reactive than Fe in series so Zn act as anode and Fe act as cathode
Ecell= -0.41-(-0.76)
= +0.35V
Ecell= -0.41-(-0.76)
= +0.35V