Solve this:
Q.3. A mass m supported by a massless string wound around a uniform hollow cylinder of mass m and radius R. If the string does not slip on the cylinder, with what acceleration will the mass fall on release?


(a) 2 g 3
(b) g 2
(c) 5 g 6
(d) g

Dear student,
According to question the moment of inertia is I = 
mR2   (for hollow cylinder)
a= α R     .............1>     (for no slipping condition)a =mg -Tm       ........2>   (for linear motion)α = RTI =RTmR2             (for rotational motion)aR =RTmR2 T = ma    ...........3>now put value of T in eq 2a =mg - mam =g-a2a =ga = g/2  m/s2
Regards

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