Solve this:
Q. The solubility product of AgCl is 10 - 10   M 2 . The minimum volume (in m 3 ) of water required to dissolve 14.35 mg of AgCl is approximately :-
(1) 0.01
(2) 0.1
(3) 100
(4) 10

Dear student,
The answer is (4) i.e. 10.

Regards

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