Solve this: Q. The solubility product of AgCl is 10 - 10 M 2 . The minimum volume (in m 3 ) of water required to dissolve 14.35 mg of AgCl is approximately :- (1) 0.01 (2) 0.1 (3) 100 (4) 10 Share with your friends Share 2 Megha Sharma answered this Dear student, The answer is (4) i.e. 10. Regards 5 View Full Answer