Solve this:

Q. Wilkinson's catalyst react with H2 to form an octahedral complex in which Rh (Z = 45) has the following electronic configuration in the ligand field  t 2 g 2 , 2 , 2   ,   e g 0 . 0  Then which of the following is correct about this new complex 

  (1) It is paramagnetic

  (2) Its IUPAC  name is chlorodihydriodotris ( triphenylphosphine ) rhodium (III) 

  (3) Hybridisation of Rh (I) is d2sp3

  (4) None of these 
  
 

Dear Student,

If we see the configuration of produced complex, there is no unpaired electron , hence it would not be paramagnetic in nature. But yes its IUPAC name is chlorodihydriodotris ( triphenylphosphine ) rhodium (III), shown below:-





Hence option 2 is correct

Regards,

 

 

 

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