Solve this:
Q. Wilkinson's catalyst react with H2 to form an octahedral complex in which Rh (Z = 45) has the following electronic configuration in the ligand field Then which of the following is correct about this new complex
(1) It is paramagnetic
(2) Its IUPAC name is chlorodihydriodotris ( triphenylphosphine ) rhodium (III)
(3) Hybridisation of Rh (I) is d2sp3
(4) None of these
Dear Student,
If we see the configuration of produced complex, there is no unpaired electron , hence it would not be paramagnetic in nature. But yes its IUPAC name is chlorodihydriodotris ( triphenylphosphine ) rhodium (III), shown below:-
Hence option 2 is correct
Regards,