Solve this: Q13 For X → Y, kt +10kt=3 If the rate constant at 300 k is - Chemistry - Chemical Kinetics

Question

Solve this:

Q13 For X → Y, k t   + 10 k t = 3 If the rate constant at
300 k is 'Q' min–1, at what temperature rate
constant becomes '9Q' min –1?

1) 47 ° C 2) 320 ° C

3) 280 K 4) 9   × 300     K

Vartika Jain · Accepted Answer

Dear Student,

It is given that, Temperature coefficient, μ=kt+10kt=3and, kT2kT1=μT2-T110or, 9QQ=3T2-30010or, 9=3T2-30010or, (3)2=3T2-30010On comparing, we getT2-30010=2or, T2-300=20or, T2=320 K

Solve this: Q13. For X → Y, k t + 10 k t = 3 . If the rate constant at 300 k is 'Q' min–1, at what temperature rate constant becomes '9Q' min –1? 1) 47 ° C 2) 320 ° C 3) 280 K 4) 9 × 300 K

Solve this:

Q13. For X $\to$ Y, $\frac{k_{t} + 10}{k_{t}} = 3$ . If the rate constant at 300 k is 'Q' min^–1, at what temperature rate constant becomes '9Q' min^–1?

1) 47 $°$ C 2) 320 $°$ C

3) 280 K 4) $\sqrt{9 \times 300} K$