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Solution:

$F r o m u \sin g t h e f o l l o w i n g e q u a t i o n, M_{1} V_{1} + M_{2} V_{2} = M_{3} V_{3} [V_{3} = 1 + x) L] 0.4 \times x + 0.2 \times 1 = 0.275 (1 + x) 0.4 x + 0.2 = 0.275 + 0.275 x 0.125 x = 0.075 x = \frac{0.075}{0.125} = 0.6 M a x i m u m v o l u m e = 1 + 0.6 = 1.6 L$
Here, xL of 0.4 M HCl solution is mixed.

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