The equivalent conductance of M/32 solution of a weak monobasic acid is 8.0 mhos cm^2 and at infinite dilution is 400 mhos cm^2. The dissociation constant of the acid is
1- 1.25 x 10^-4 2- 1.25 x 10^-5
3- 1.25 x 10^-6 4- 6.25 x 10^-4
The degree of dissociation is related to equivalent conductance and equivalent conductance at infinite dilution :
The degree of dissociation α = Λ(equivalent conductance at given dilution)/Λ∞(equivalent conductance at given dilution)
= 8 mho cm2/400 mho cm2
Dissociation constant of an acid Ka = C α2
= 1/32 M x (8 mho cm2/400 mho cm2)2
= 1.25 x 10-5
Correct answer is 2.
The degree of dissociation α = Λ(equivalent conductance at given dilution)/Λ∞(equivalent conductance at given dilution)
= 8 mho cm2/400 mho cm2
Dissociation constant of an acid Ka = C α2
= 1/32 M x (8 mho cm2/400 mho cm2)2
= 1.25 x 10-5
Correct answer is 2.