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The halide of a metal MX crystalizes as ccp structure (NaCl type). If all the atoms situated at one of the tetrad axis are removed then what will be the simplest molecular formula of halide

a) MX

b) M_{3}X_{4}

c) MX_{2}

d) MX_{3}

The computation is expressed below,

NaCl representation is,

$No.of\text{\'}M\text{\'}atoms=(8\times \frac{1}{8})+(4\times \frac{1}{2})=1+2=3\phantom{\rule{0ex}{0ex}}No.of"X"atoms=(12\times \frac{1}{4})+(1\times 1)=3+1=4\phantom{\rule{0ex}{0ex}}Hencetheatomis{M}_{3}{X}_{4}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}AnswerisOption\left(B\right)$

Regards.

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