the middle term in the expansion of (2x2/3+3/2x2)10 is?? Share with your friends Share 1 Manbar Singh answered this The given expansion is, 2x23 + 32x210Total number of terms in the given expansion is 11.So, the middle term = 11 + 12th term = 6thterm = T5+1We know that Tr+1 = Crn an-r br⇒ T5+1 = C510 2x2310-5 32x25 as, a = 2x23 and b = 32x2⇒ T5+1 = C510 2x235 32x25⇒ T5+1 = C510 32x10243 × 24332x10⇒ T5+1 = 10!5! 10 - 5!⇒ T5+1 = 10!5! 5! = 10 × 9 × 8 × 7 × 6 × 5!5! 5! = 10 × 9 × 8 × 7 × 65 × 4 × 3 × 2 × 1 = 252∴ middle term of the given expansion is 252. 10 View Full Answer Nevil Mathew answered this is.... 4