the number of dissimilar terms in (x+1/x+ x^2 + 1/x^2)^15 are - Maths - Binomial Theorem

Question

the number of dissimilar terms in (x+1/x+ x^2 + 1/x^2)^15 are ?

Vivek Rai · Accepted Answer

Dear student
(x+1x+x2+1x2)15=(x3+x+x4+1x2)15=1x30(1+x+x3+x4)15Now,in  (1+x+x3+x4)15, we get the powers of x0,x1,x2
x60so there will be in total 61 terms
Every term when divided by x30 wil again gives dissimilar terms
Hope this clears your doubt
With regards