the number of electrons needed to reduce 3g of mg+2 to mg
a)N b) N/2 c)N/4 d)N/8

Dear Student,
To reduce  on  Mg²⁺ number of electrons required = 2

Mass of Mg=24g

Number of moles in  3g=3/24=1/8
Avogadro number  N = (6.022$\times$10²³)

hence, number of atoms= N/8

Therefore to reduce N/8  Mg²⁺ atom, number of electrons required = 2$\times$N/8

   = N/4
Regards