The organic (P) of the reaction.
Dear Student,
Alcoholic KOH undergoes dehydrohalogenation. Therefore, a Br atom along with a β-hydrogen will eliminate leaving a double bond behind.
Hence, the correct answer is (B)
Alcoholic KOH undergoes dehydrohalogenation. Therefore, a Br atom along with a β-hydrogen will eliminate leaving a double bond behind.
Hence, the correct answer is (B)