The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the is how many times greater than that of B from the sun

TA = 8 TBAccording to kepler's third law -TATB2=RARB3RARB=TATB23RARB= 8 TBTB23RARB=23×23=22=4RA=4RB

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