# the quantity of electricity required to reduce 12.3g of nitro benzene to aniline assuming 50% current efficiency is1) 115800C2) 57900C3) 231600C4) 28950C

The reduction of Nitrobenzene can be written as:
C6H5NO2 + 6H+ + 6e-$\to$C6H5NH2 + 2 H2O
Molar mass of Nitrobenzene = 123 g
123 g of nitrobenzene use 6 moles electron for complete reduction.
So 12.3 g of nitobenzene would use = 6/123 x 12.3 = 0.6 mole electrons
Amount of charge in 0.6 mole electron = 0.6 x 96500 = 57900 C
​But the efficiency of current is 50 % so it would require twice amount of charge
Therefore the amount of charge required = 57900 x 2 = 115800 C.
So, the correct option is a)

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