the quantity of electricity required to reduce 12.3g of nitro benzene to aniline assuming 50% current efficiency is

1) 115800C

2) 57900C

3) 231600C

4) 28950C

The reduction of Nitrobenzene can be written as:
C₆H₅NO₂ + 6H⁺ + 6e^-$\to$C₆H₅NH₂ + 2 H₂O
Molar mass of Nitrobenzene = 123 g
123 g of nitrobenzene use 6 moles electron for complete reduction.
So 12.3 g of nitobenzene would use = 6/123 x 12.3 = 0.6 mole electrons
Amount of charge in 0.6 mole electron = 0.6 x 96500 = 57900 C
​But the efficiency of current is 50 % so it would require twice amount of charge
Therefore the amount of charge required = 57900 x 2 = 115800 C.
So, the correct option is a)