The solution for this question does not math the correct option given :
Q6. Madhav during an inorganic experiment treated magnesium ribbon with sulphuric acid and observed an evolution of a gas. He stored the gas in a flask having a capillary tube. To predict the nature of the gas, he brought a lighted matchstick near the mouth of the capillary tube and observed that the matchstick went off followed by a pop sound. He concluded it to be hydrogen. When he treated the magnesium ribbon with conc. HCI, no characteristic observation was made. This is probably due to:
(A) NO– 3 ion is reduced in preference to hydronium ion
(B) Conc. HNO3 is a weaker acid than conc. H2SO4 and conc. HCI
(C) Conc. HNO3 acts as a reducing agent
(D) Magnesium is more reactive than H2
Dear Student, The answer will be D however the solution provided is not correct. Mg being more reactive than hydrogen will displace hydrogen from sulphuric acid to give hydrogen gas which will burn with a pop sound. Regards,