the vapour pressure of pure benzene at 25*c is 639.7 mm of Hg and vapour pressure of solute in benzene at the same temprature is 631.9 mm of Hg. calculate the molality
Given,
p = 639.7 mm
ps = 631.9 mm
Let n moles of solute are dissolved in 1000 g of C6H6.
And
Number of moles of solvent C6H6, (N) = 1000/78 (molar mass of C6H6 = 78 g)
Now,
.bmp)
Hence, molality of the solution is 0.156 m
p = 639.7 mm
ps = 631.9 mm
Let n moles of solute are dissolved in 1000 g of C6H6.
And
Number of moles of solvent C6H6, (N) = 1000/78 (molar mass of C6H6 = 78 g)
Now,
Hence, molality of the solution is 0.156 m