The velocity of a car increases from 30km/hr to 45km/hr in 5 minutes. Assuming the acceleration to be uniform calculate the distance travelled.
Hello Kiara dear, shall we use v = u + a t to get the value of acceleration?
Given u = 30 km p h
and v = 45 km p h
And time = 5 min = 1/12 h
Plug and you can get acceleration a = 180 km p h^2
Now we have to use v^2 = u^2 + 2 a S
So required distance S = v^2 - u^2 / 2a Or (v+u) (v-u) / 2 a
Plugging we have S = 75 * 15 / 2 * 180 = 75/24 km = 3.125 km
Given u = 30 km p h
and v = 45 km p h
And time = 5 min = 1/12 h
Plug and you can get acceleration a = 180 km p h^2
Now we have to use v^2 = u^2 + 2 a S
So required distance S = v^2 - u^2 / 2a Or (v+u) (v-u) / 2 a
Plugging we have S = 75 * 15 / 2 * 180 = 75/24 km = 3.125 km