three moles of an ideal gas are compressed isothermally and reversibly to a volume of 2L. the work done is 2.983 kJ at 295 K. calculate the initial; volume of the gas pls show log calculations experts pls ans it fast its urgent.... Share with your friends Share 19 Geetha answered this W= -2.303 nRT log V2V1 2.983 × 103 = -2.303 × 3× 8.314 × 295× log 2V1 = -2.303 × 3 × 8.314 × 298 × (log 2 - log V1)- (log 2 - log V1) = 2.983 × 103 2.303 × 3 × 8.314 × 298 = 0.1743log V1 - log 2 = 0.1743log V1 = 0.1743 + log 2 = 0.1743 + 0.3010 = 0.4753V1 = A.log ( 0.4753) = 2.987 L 14 View Full Answer