three moles of an ideal gas are compressed isothermally and reversibly to a volume of 2L. the work done is 2.983 kJ at 295 K. calculate the initial; volume of the gas 
pls show log calculations
experts pls ans it fast its urgent....

W= -2.303 nRT log V2V1  2.983 × 103  = -2.303 × 3× 8.314 × 295× log 2V1  = -2.303 × 3 × 8.314 × 298 × (log 2 - log V1)- (log 2 - log V1) = 2.983 × 103  2.303 × 3 × 8.314 × 298 = 0.1743log V1 - log 2 = 0.1743log V1 = 0.1743 + log 2          = 0.1743 + 0.3010      = 0.4753V1 = A.log ( 0.4753)   = 2.987 L

  • 14
What are you looking for?