Two carnot engine A and B are operated in series.The first one A receives hat at 800K and rejects to a reservoir at TK. The second engine B receives the heat rejected by the first engine and in turn rejects to a heat reservoir at 300K.Calculate the value of T ,when outputs of the two engines are equal.
Let the output of both engines be W
Let the 1st engine take Q1 heat as input at temperature T1 = 800K and gives out heat Q2 at temperature T the second engine receive Q2 as input and give out Q3 at temperature T3 = 300k to the sink.
Work done by first engine W = Q1 – Q2
Work done by 2nd engine W = Q2 – Q3
Thus,
Q1 – Q2 = Q2 – Q3
Dividing both sides by Q1
1 – Q2/Q1 = Q2/Q1 – Q3/Q1
=> 1-T/T1 = Q2/ Q1(1- Q3/ Q2)
=> 1-T/T1 = Q2/ Q1(1- T3/ T)
=> 1-T/T1 = T/T1 (1- T3/ T)
=> T1/T – 1 = 1 - T3/ T
=> T1/T + T3/ T = 2
=> 1/T (T1 + T3) = 2
=>T = (T1 + T3)/2
=> T = (800+300)/2 = 550 K