Two carnot engine A and B are operated in series.The first one A receives hat at 800K and rejects to a reservoir at TK. The second engine B receives the heat rejected by the first engine and in turn rejects to a heat reservoir at 300K.Calculate the value of T ,when outputs of the two engines are equal.

Let the output of both engines be W

Let the 1st engine take Q1 heat as input at temperature T1 = 800K and gives out heat Q2 at temperature T the second engine receive Q2 as input and give out Q3 at temperature T3 = 300k to the sink.

Work done by first engine W =  Q1 – Q2

Work done by 2nd engine W = Q2 – Q3

Thus,

 Q1 – Q2 = Q2 – Q3

Dividing both sides by Q1

1 – Q2/Q1  = Q2/Q1 – Q3/Q1

=> 1-T/T1 = Q2/ Q1(1- Q3/ Q2)

=> 1-T/T1 = Q2/ Q1(1- T3/ T)

=>  1-T/T1 = T/T1 (1- T3/ T)

=> T1/T – 1 = 1 - T3/ T

=> T1/T + T3/ T = 2

=> 1/T (T1 + T3) = 2

=>T = (T1 + T3)/2

=> T = (800+300)/2 = 550 K

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