two Faraday of electricity is passed through a solution of cuSo4.the mass of copper deposited at cathode is: at.mass of Cu= 63.5amu Share with your friends Share 16 Geetha answered this W = ZItWhere W - amount of substance depositedZ= electrochemical equivalentI- amount of current passedt= time It = Q = 2FZ= atomic massnF =63.52F (Since in CuSO4 Copper exist as Cu2+)W = 63.52F × 2F = 63.5 g 52 View Full Answer
