two particles A and B each of mass m are connected by a massless string. A is placed on a rough table. The string passes over a small , smooth peg. B is left from a position making angle theta with the vertical . If the minimum coeffient of friction between A and table is umin=3-Ncostheta so that A does not slip during the motion of mass B. then calculate the value of N


Masses are placed as shown in the diagram.In balancing condition following are the eqns of motion.ma =Tsinθ---1  mg=Tcosθ ---2and    R = mg---3         T = (3-N cosθ)R = (3-N cosθ)mg---4from eqns 2 and 4, we get,mgcosθ =  (3-N cosθ)mgor     1 = 3 cosθ-N cos2θor    N =3cosθ-1 cos2θ = 3 secθ -sec2θ. 

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