two springs have force constant K1 and K2 (k1k2) . EACH SPRING IS EXTENDED BY SAME FORCE f , IF THEIR elastic potential energy are E1 and E2 then, E1/E2 IS = ?

The expansion of 1st spring,
Δx1=fk1
The expansion of 2nd spring,​
Δx2=fk2
Then,
E1E2=12k1(Δx1)212k2(Δx2)2=12k1f2k1212k2f2k22=k2k1

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