two tuning forks A and B produce 4 beats/sec.On loading B with wax, 6 beats/sec are heard.If quantity of wax is reduced, the number of beats per second again becomes 4.Find the frequency of B if the frequency of B if the frequency of A is 256 hz?

Let the unknown frequency of the tuning fork be 'x'. So, according to the given data when not waxed, its frequency must be,

x = 256 +/- 4 to produce a beat of 4/sec.

We know, the frequency of a tuning fork decreases as it is waxed. So, to produce 6 beats/sec, after being waxed, the frequency of the tuning fork must be x = 256 - 4 = 252 Hz.

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