Vapour pressure of water at 293 K is 17.51 mm. Lowering of vapour pressure of a sugar solution is 0.0614 mm. Calculate the relative lowering of V.P.

Dear Student,

Please find below the solution to the asked query:

The vapour pressure of the solvent, is given as:  $p_1^o=17.51 mmHg$

The lowering of the vapour pressure upon adding the non-volatile solute is given as: $∆p_1=p_1^o-p_1=0.0614 mmHg$

Then, the relative lowering of vapour pressure is equal to: $\frac{∆p_1}{p_1^o}=\frac{0.0614 mmHg}{17.51 mmHg}=\mathbf{3}\mathbf{.}\mathbf{51}\mathbf{\times }{\mathbf{10}}^{\mathbf{-}\mathbf{3}}$


Hope this information will clear your doubts about Solutions.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.

Best Wishes !