Water is pumped out of a well 10m deep by means of a pump rated at 10KW.Find the efficiency of the motor of 4200 kg of water is pumped out every minute.given g=10 m/s squqre
Dear Student,
Potential Energy Gained by water in 60 sec= 4200 x 10 x 10 = 4.2 x 10 5 J ( output)
Energy spend by pump( work done by pump)= P x t = 10 x 103 x 60 = 6x 10 5 J ( input)
Regards.
Potential Energy Gained by water in 60 sec= 4200 x 10 x 10 = 4.2 x 10 5 J ( output)
Energy spend by pump( work done by pump)= P x t = 10 x 103 x 60 = 6x 10 5 J ( input)
Regards.