Water is pumped out of a well 10m deep by means of a pump rated at 10KW.Find the efficiency of the motor of 4200 kg of water is pumped out every minute.given g=10 m/s squqre

Dear Student,

Potential Energy Gained by water in 60 sec= 4200 x 10 x 10 = 4.2 x 10 J  ( output)

Energy spend by pump( work done by pump)= P x t = 10 x 103 x 60 = 6x 10 5 J   ( input)

Efficiency= Work outputWork input×100=4.26×100=0.7 × 100=70 %

Regards.
 

  • 4
What are you looking for?