what is the activation energy for a reaction whose rate constant doubles when temerature changes from 30 to 40 Share with your friends Share 0 Vartika Jain answered this Dear Student, we know that, log k2k1=Ea2.303R(1T1-1T2)Here, k2=2k1T2=40°C = 40+273=313KT1=30°C = 30+273=303KSo, log 2k1k1=Ea2.303×8.314(1303-1313)or, log 2=Ea19.147(313-30394839)or, Ea = 0.3010×19.147×9483910 =54658.05 Jmol-1 =56.658 kJmol-1 2 View Full Answer Vishav Gupta answered this Put temp..by ur own and solve....!!! 2
