What must be concentration of Ag+ in an aqueous solution containing Cu2+=1.0 M so that both the metals can be deposited on the cathode simultaneously. Given that E0 cu/cu 2+ =-0.34 and E0 Ag + /Ag = 0.812V,T= 298K

Dear Hardee Shah,

For both the metals to get deposited on cathode the Eocell = 0 Eo Cu2+/Cu = 0.34;  Eo Ag+/Ag = 0.812Eocell = EoAg+/Ag- Eo Cu2+/Cu=0Eocell = {EoAg+/Ag +0.05911log [Ag+]} - {Eo Cu2+/Cu+0.05912log [Cu2+]}0 = {0.812 +0.0591 log  [Ag+]} - {0.34 + 0.02955 log 1}log [Ag+] = 0.34-0.8120.0591=-7.986[Ag+]=10-7.986=1.03 ×10-8

Regards

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