What percentage of carbon is contained by 0.2 gram of hydrocarbon which gives 0.506 gram of carbon dioxide on complete combustion

Dear Student,

CxHy  +  O2 (excess)  CO2  +  H2O 0.44g                                    0.88 g       1.8g                                       44 g of CO2 contains 12 g of CTherefore, 0.88g of CO2 contains 1244× 0.88 = 0.24 g of CNow, 18g of H2O contains 2g of HTherefore, 1.8 g of water will contain 218× 1.8 = 0.2 g of HNow according to Law of Conservation of Mass,Mass of reactant = Mass of productSince O2 is in excess, we can ignore it and  since only C and H are present in the reactant we will only add amount of C and H in the product.0.44 g = 0.24 g + 0.2 g 0.44 g = 0.44 gThe amount of carbon in 0.506 gm CO2 = 12/44 x 0.506 = 0.138 gm

similarly amount of H in 0.1014 gm of H2O = 2/ 18 x 0.1014 = 0.011 gm

As the compound completely burns giving only CO2 and H2O in presence of oxygen, 

Here, total amount of carbon and hydrogen in compound = 0.138 + 0.011 = 0.149 gm

Hence , %age composition of Hydrogen = 0.011/ 0.149x 100  = 7.38 %

Similarly %age of Carbon = 0.138/ 0.149 x 100  = 92.61 %

Regards.

Note: The gram of water is not given in question statement hence the computation are performed using standard value of water mass.

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