what volume of 75% sulfuric acid by mass is required to prepare 1.5 Lt of 0.2 M sulfuric acid solution ??
Moles of H2SO4 = c V
where, c is concentration in molarity = 0.2 M
V is volume in litres= 1.5 L
Substituting the values, moles = 0.2 1.5 = 0.3 moles
Mass of sulphuric acid = moles molar mass = 0.3 98 = 29.4 g
Concentration of H2SO4 solution =75%
75 g of H2SO4 is present in 100 ml
29.4 g of H2SO4 is present in =
39.2 ml of 75% solution is required to prepare 1.5 L of 0.2 M H2SO4 solution.
where, c is concentration in molarity = 0.2 M
V is volume in litres= 1.5 L
Substituting the values, moles = 0.2 1.5 = 0.3 moles
Mass of sulphuric acid = moles molar mass = 0.3 98 = 29.4 g
Concentration of H2SO4 solution =75%
75 g of H2SO4 is present in 100 ml
29.4 g of H2SO4 is present in =
39.2 ml of 75% solution is required to prepare 1.5 L of 0.2 M H2SO4 solution.