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When a body is placed on a smooth inclined plane it slides down without any accleration.when the angle of inclination is 150. if the angle of inclination is increased by 150.What will be the acceleration of the same body

@ maria:  When the body is sliding down on a frictionless inclined plane, gravitational force acting downward which is equals to the  weight of the body get resolve into two normal components as your friend pradeep has shown in his answer

Horizontal component i.e. mg cosθ will get balance by the normal reaction of the weight which should also be normal to the  inclined plane while other will contribute to the downward acceleration of the body, as a result 

downward acceleration of the body = g sinθ, where θ is the angle of inclination

Since 

sin 15 < sin 30

Value of the acceleration will increase

@ pradeep: keep it up! very good attempt.

  • -6
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(g = 10 m/s) i need calculations !!

  • -4

when the body is on the inclined plane and in the absence of any friction it slides down with g*sin15o.

and when the angle is increased then sin A also increases.

so acceleration will increase.



as youu can see here g*sinA is acting on the block in absence of any friction and external acceleration.


hope it helps!!

cheers!!!

thumbs up plzzz

  • -6

Thnx for ur effort! but i m nt able to understand!..srry

  • 6

On an inclined plane ; if the external acceleration i.e. the acceleration which is produced by any force acting on the block other than gravity is zero then the only acceleration due to which block is sliding is due to gravity & it has two components

(1) along the direction in which block slides = g sin(theta)

(2) along the direction opposite to Normal Reaction that acts on the block due to inclined plane (Which is canceled by the perpendicular component of gravity 'g') = g cos(theta)

So only one component of gravity 'g' acts  which is in the direction in which slides & is equal to g sin(theta)

So , when the anle  ' theta ' is increased then sin (theta) also increases & therefore , g sin(theta) increase

& hence the acceleration of the body is increased..

 

  • -3

On an inclined plane ; if the external acceleration i.e. the acceleration which is produced by any force acting on the block other than gravity is zero then the only acceleration due to which block is sliding is due to gravity & it has two components

(1) along the direction in which block slides = g sin(theta)

(2) along the direction opposite to Normal Reaction that acts on the block due to inclined plane (Which is canceled by the perpendicular component of gravity 'g') = g cos(theta)

So only one component of gravity 'g' acts  which is in the direction in which slides & is equal to g sin(theta)

So , when the anle  ' theta ' is increased then sin (theta) also increases & therefore , g sin(theta) increase

& hence the acceleration of the body is increased..

 

  • 1

On an inclined plane ; if the external acceleration i.e. the acceleration which is produced by any force acting on the block other than gravity is zero then the only acceleration due to which block is sliding is due to gravity & it has two components

(1) along the direction in which block slides = g sin(theta)

(2) along the direction opposite to Normal Reaction that acts on the block due to inclined plane (Which is canceled by the Normal Reaction') = g cos(theta)

So only one component of gravity 'g ' acts which is in the direction in which the block slides & is equal to g sin(theta)

So , when the angle ' theta ' is increased then sin (theta) also increases & therefore , g sin(theta) increase

& hence the acceleration of the body is increased..

  • -4
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