when the speed of the car is v the minimum distance over which it can be stopped is x. if the speed becomes nv,what will be the minimum distance over which it can be stopped during same time?

Hi Rohini,

Here, speed of the car = v
let stopping distance be x when speed is v

Since s = u^2/2a

​ => 2a = v^2/2x          (1)

​When the speed is nc ,the stopping distance is x

=> s = (nv)^2/2a 
=>  s = n^2v^2/v^2/x     (By (1) 2a = v^2/2x )
=> s = n^2x

therefore , the minimum distance over which the car can be stopped when the speed is n is n^2x.


Hope this is helpful.