Which of the following complex has maximum CFSE :-
(1) [NiCl4]–2
(2) [NiBr4]–2
(3) [NiCl6]–4
(4) [Ni(SCN)4]–2

Dear Student,

(1), (2) and (4) will forms tetrahedral complexes due to the presence of four weak ligands and (3) will form octahedral complex due to the presence of six weak ligands.
Now, we know that CFSE of octahedral is greater than CFSE of tetrahedral as splitting is greater in octahedral complexes.
Therefore, the correct answer is (3)

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