why don't we use Afbau principle in this case while filling the orbitals?
Dear student
Please find below the solution to the asked query:
Aufbau Principle should always be followed while writing electronic configuration. Transition metals are d block elements and include 3d, 4d and 5d shells of electrons.Unlike s and p block elements,in d block elements, electrons are added to the penultimate shell, expanding it from 8 to 18 electrons. In the atoms of these elements the outermost shell and the penultimate shell are incomplete.
General electronic configuration of transition metals is : (n-1)d1-9ns0 or 1 or 2
The compound [NiCl4]2- , has sp3 hybridization which is determined as:
At step 1: we find the metal cation and as, x + (-4) = -2 or x = +2, So, metal ion is Ni2+ ion , whose configuration is 3d8
Step2 : Further, Cl, forms high spin complex , it could not pair up the unpaired electrons of 3d-orbital and so the four electrons pair donated by Cl-atoms are arranged in 4 sp3 hybridized orbitals.
The detailed mechanism is given as below:
Hope this information will clear your doubts regarding the topic.
If you have any other doubts please ask here on the forum and our experts will try to solve them as soon as possible.
Regards
Please find below the solution to the asked query:
Aufbau Principle should always be followed while writing electronic configuration. Transition metals are d block elements and include 3d, 4d and 5d shells of electrons.Unlike s and p block elements,in d block elements, electrons are added to the penultimate shell, expanding it from 8 to 18 electrons. In the atoms of these elements the outermost shell and the penultimate shell are incomplete.
General electronic configuration of transition metals is : (n-1)d1-9ns0 or 1 or 2
The compound [NiCl4]2- , has sp3 hybridization which is determined as:
At step 1: we find the metal cation and as, x + (-4) = -2 or x = +2, So, metal ion is Ni2+ ion , whose configuration is 3d8
Step2 : Further, Cl, forms high spin complex , it could not pair up the unpaired electrons of 3d-orbital and so the four electrons pair donated by Cl-atoms are arranged in 4 sp3 hybridized orbitals.
The detailed mechanism is given as below:
Hope this information will clear your doubts regarding the topic.
If you have any other doubts please ask here on the forum and our experts will try to solve them as soon as possible.
Regards