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why is adiabatic curve more steeper than isotherm curve?

because slope of adiabatic curve is defined by -yP/V while that of isothermal is -P/V....clearly the slope of adiabatic is more ne therefore it is more steeper

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 PV =constant     pdv+vdp=0    dp/dv= -p/v  ..    

 adiabatic curve

PV^gamma = const    pdv^gamma + v^gamma dp = 0    gamma p/v = -dp/dv ..    thus, dp/dv adiabatic  ==  -gamma(p/v)

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Best Answer:  Isothermal eqn is PV=const it linear graph is 
logP=-logV 
Adiabatic eqn is 
PV^y=const y=C(p)/C(v) C(p)>C(v) 
its linear form is 
logP=-ylogV 
and y>1 so the slop is more(steep) in adiabatic. 
IVAN
 
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Pv adiabatic is more steeper than pv isotherm
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Isothermal eqn is PV=const it linear graph is?
logP=-logV?
Adiabatic eqn is?
PV^y=const y=C(p)/C(v) C(p)>C(v)?
its linear form is?
logP=-ylogV?
and y>1 so the slop is more(steep) in adiabatic.?
IVAN
?
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