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Syllabus

1.Find the missing frequency f, if the mode of the given data is 154.

Classes

120-130

130-140

140-150

150-160

160-170

170-180

Frequency

2

8

12

f

9

7

plzz give an answer fast....

how to calculate mode if two classes have same and highest frequency (bimodal) ?

what is hit and trial method .

The mean of the following data is 38.2. Find the missing frequencies f1 and f2 if the total frequency is 50.

Classes

0-10

10-20

20-30

30-40

40-50

50-60

60-70

Frequency

4

4

F1

10

F2

8

5

If the median of the distribution is given below is 28.5, find the values of

xandy.Class intervalFrequency0 − 10

5

10 − 20

x20 − 30

20

30 − 40

15

40 − 50

y50 − 60

5

Total

60

if the median of the following frequency distribution is 24. find the missing frequency x :

Age Number of persons

0 - 10 5

10 - 20 25

20 - 30 x

30 - 40 18

40 - 50 7

Find the value of f1 from the following data if it's mode is 65:

Class frequency

0-20 6

20-40 8

40-60 f1

60-80 12

80-100 6

100-120 5

Where frequency 6,8, f1, and 12 are in ascending order.

find the missing frequencies if N=100 and median is 32.

marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total

no. of students-10 ,? ,25 ,30 ,? ,10 ,100.

_{1 }, f_{2}and f_{3}in the following frequency distribution , when it is given taht f_{2 }: f_{3}= 4 : 3 , and mean = 5020-40

40-60

60-80

80-100

17

f

_{1}f

_{2}f

_{3 19}The median of the following distribution is 30. Find the missing frequencies f1 and f2:

Class frequency

0-10 10

10-20 10

20-30 f1

30-40 30

40-50 f2

50-60 10

Total 100

Height No. of students.

125-130 2

130-135 4

135-140 x

140-145 y

145-150 8

150-155 9

155-160 5

the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?

Class : 50 –55 55 – 60 60 – 65 65 – 70 70 – 75 75 – 80

Frequency : 2 8 12 24 38 16

how to find the mean if the class intervals are unequal??

like fr e- 0-10,10-30,30-35....

IF THE N/2 IS EQUAL TO THE CUMULATIVE FREQUENCY THEN WE WOULD REGARD THAT CLASS AS THE MEDIAN CLASS OR NOT.

The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______

Find the median of the following data.

Wages ( in rupees ) :More than 150 , More than 140 , More than 130 , More than 120 , More than 110 , More than 100 , More than 90 . More than 80.No.of workers : NIL ,12,27,60,105,124,141,150.how to find xi?

Find the median of the following data.

Classes

118-126

127-135

136-144

145-153

154-162

163-171

172-180

Frequency

3

5

9

12

5

4

2

In the step deviation method,

What is the meaning of

u_{i }?What is the formula to use median when more than ogive is given?

Class 0 – 20 20 – 40 40 – 60 60 – 80 80 –100 100 –120

Frequency 6 8 f 12 6 5

8. The mean of the following distribution is 53. Calculate missing frequencies

median.

Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90

frequency 10 8 12 24 6 25 15

(in years)

(A)

(B)

Find the modal age of employees in factory A and B.

A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Number of days0 − 6

6 − 10

10 − 14

14 − 20

20 − 28

28 − 38

38 − 40

Number of students11

10

7

4

4

3

1

Cost of living index /number of weeks

1400-1500—8

1550-1700—15

1700-1850—21

1850-2000—8

Marks Below 10 Below 20 Below 30 Below 40 Below 50 Below 60 Below 70 Below 80 Below 90 Below 100

No. of students 5 9 17 29 45 60 70 78 83 85

6,3,5,7,10,7,8,10,2,1,7,10,p - 2

3 Median = Mode + 2 Mean

please proof it.

Class Interval

20-30

30-40

40-50

50-60

60-70

Frequency

25

47

62

p

10

In a continuous frequency distribution, the median of the data is 21.If each observation is increased by 5 find the new median

53 – 55

56 – 58

59 – 61

62 – 64

120

105

125

30

The mean and median of same data are 24 and 26 respectively. The value of mode is ?

marks number of students

0 and above 80

10 and above 77

20 and above 72

30 and above 65

40 and above 55

50 and above 43

60 and above 28

70 and above 16

80 and above 10

90 and above 8

100 and above 0

The following distribution gives the daily income of 50 workers of a factory.

Daily income (in Rs)100 − 120

120 − 140

140 − 160

160 − 180

180 − 200

Number of workers12

14

8

6

10

Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.

the mean of first n odd natural numbers is n2/81,then n=

Q1) among the following which is not the measure of central tendency?

A) Mean B) Median C) Mode D) range

Q2) among the following which is the best measure of central tendency?

A) Mean B) Median C) Mode

if the mean of the following frequency distribution is 91, find the missing frequency x and y :

classes frequency

0 - 30 12

30-60 21

60 - 90 x

90 -120 52

120 - 150 y

150 - 180 11

total 150

The mean of n observations is X . IF the first item is increased by 1, second by 2 and so on, then the new mean is:

1. X+n

2. X+n/2

3. X+(n+1)/2

4. X+(n-1)/2

The median of the following data is 20.75. Find the missing frequencies x and y, if the total frequency is 100.

Class interval:-0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40

Frequencies: -7 10 x 13 y 10 14 9

class frequency

40-50 5

50-60 x

60-70 15

70-80 2

80-90 7

Number of teachers 4, 3 ,18, 2, 3 Find mean and median for this data.

how do we find mean using step deviation method if the classes are unequal?

should we make the classes equal in such a case?

13. Find the mean, mode and median for the following data:

During the medical check-up of 35 students of a class, their weights were recorded as follows:

Weight (in kg)Number of studentsLess than 38

0

Less than 40

3

Less than 42

5

Less than 44

9

Less than 46

14

Less than 48

28

Less than 50

32

Less than 52

35

Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.

Class interval Frequency0-10 10

10-20 20

20-30 x

30-40 40

40-50 y

50-60 25

60-70 15

age no of cases

5-14 6

15-24 11

25-34 21

35-44 23

45-54 14

55-64 5

Find the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 from

their mean.

Class interval Frequency10-20 12

20-30 30

30-40 f1

40-50 65

50-60 f2

60-70 25

70-80 18

no links plz.

in a grouped frequency distribution,the class with the maximum frequency is called?

a.mean class b.median class c.modal class d.distribution class

the median of the data is 525. find x and y, if total frequency is 100

class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000

frequeency 2 5 x 12 17 20 y 9 7 4

9. If the mean of the distribution is 57.6 and the sum of its observations is 50, find the missing

The mean of the following frequency dristibution is 50. Find the value of

ppIn a school 85 boys and 35 girls appeared in a public examination . The mean marks of the boys were found to be 40 % whereas the mean marks of the girls were 60% . Determine the average marks % of the school.

In a given data if the MODAL CLASS is at the bottom(last) and has nothing Preceeding it then how will we find the MODE?

how can we find the median by only less than ogive curve?

The median of the following data is 32.5.find the value of x and y

class interval f

0-10 x

10-20 5

20-30 9

30-40 12

40-50 y

50-603

60-70 2

total 40

C.I. F

45-55 7

55-65 12

65-75 17

75-85 30

85-95 32

95-105 6

105-115 10

The following table shows the marks obtained by 100 students of class X in a school during a particular academic session. Find the mode of this distribution.

Marks No. of studentsLess than 10 7

Less than 20 21

Less than 30 34

Less than 40 46

Less than 50 66

Less than 60 77

Less than 70 92

Less than 80 100

Find the mean, mode and median for the following data.

Shopkeepers of a shopping complex decided to donate money for education for poor children.The following distribution gives the annual profit earned by 30 shops of that shopping complex.

Profit

(in lakhs Rs.) 0-5 5-10 10-15 15-20 20-25

No. of shops 3 14 5 6 2.

(a) change the above distribution to more than type

distribution and draw its ogive.

(b) What is the value depicted by the shopkeeper..

d

_{i}is the deviation of x_{i }from assumed mean a.If mean = x + ∑f

_{i}d_{i}/∑f_{i}, then x ismonthly consumption of electricity of some consumers is given below as a distribution. Find the missing frequency(x), if mode is given to be 200 units.

Monthly cosumption(in units ) 90-120 120-150 150-180 180-210 210-240

Number of consumers 20 15 X 75 30

how to find the median class?

18 - 23

x 23- 28 170 28- 33 y 33- 38 50 38- 43 3843-48

48-53

10

2

the frequency distribution table shows the ages of 560 girls at the time of their marriage in a city. If mode of the age of the data is 24 years, find missing frequency.

How to find missing frequency if the mode of the given data is given.

How to convert a

LESS THAN OGIVEand it'sCFinto the Frequency distribution?The median from the table is

value 7, 8, 9, 10, 11, 12 ,13

frequency 2, 1, 4, 5, 6, 1, 3

Find the class marks of classes 10 - 25 and 35 - 55.if the arithmetic mean of the following distribution is 56, find the missing frequencies f1 and f2

If the mean of the following distributions is 27, Find the value of p

classes frequency

40-50 5

50-60 x

60-70 15

70-80 y

80-90 7

total 47

If the less than ogive and more than ogive intersect each other at ( 20.5,15.5 ), then the median of the given data is :

A ) 36.0 B) 20.5 C ) 15.5 D ) 5.5

Marks obtained 5-10 10-15 15-20 20-25

Cf. 30. 23. 8. 2

Change the above due to a continuous grouped frequency distribution

The mean of the following data is 53, find the missing frequencies.

age in years -- 0-20, 20-40 40-60 60-80, 80-100

number of people--- 15, f1, 21, f2, 17, 100

Mode and mean of a data are 12k and 15k. Median of the data is

Total = 50

height in cm frequency cumulative frequency

150-155 12 a

155-160 b 25

160-165 10 c

165-170 d 43

170-175 e 48

175-180 2 f

What is the difference between frequency and cumulative frequency.

the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find

a) class size

b) lower limit of second class

c) upper lmit of last class

d) third class

If x bar is the mean of a distribution, then ∑fi(xi - x bar) is equal to