1) ABCD is a paralellogram. X and Y are mid points of BC and CD respectively.Prove that area (AXY) = 3/8 area(paralellogram ABCD)
2) In a triangle ABC P and Q are respectively the mid points of AB and BC and R is the mid point of AP. Prove that:
1) area(PRQ) =1/2 area(ARC)
2) area(RQC) = 3/8 area(ABC)
3) area(PBQ) = area(ARC)
ABCD is a trapezium in which AB is parallel to DC. DC=30 cm. and AB=50cm. if X and Y are respectively the mid points of AD and BC, prove that (Nine times the area of DCYX= seven times the area of XYBA.)
if the medians of a triangle ABC intersect at G show that ar ( AGB ) = ar(AGC)=ar(BGC)=1/3 ar(ABC).
prove that two triangles having the same base (or equal bases) and equal areas lie between the same parallels.
prove that median divides triangle into two equal parts
The median BE and CF of a triangle ABC intersect at G. prove that area of triangle-GBC = area of quadrilateral AFGE.
Diagonals AC and BD of trapezium ABCD with AB||DC intersect each other at O.
prove that ar(AOD) = ar (BOC)?
prove that the diagonals of a parallelogram divides into four triangle of an equal area
ABCD is a parallelogram in which BC is produced to E such that CE = BC(Fig. 9.17). AE intersects CD at F.If ar (DFB) = 3 cm2, find the area of the parallelogram ABCD.
in a triangle ABC,E is the midpoint of median AD. Show that area of BED = 1/4 area of ABC
The diagonals of a parallelogram ABCD intersect at point O. Through O, a line is drawn to intersect
AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal areas.
P and Q are respectively the mid points of side AB and BC of a triangle ABC and R is the mid point of AP show that,
{1} ar(PQR)= 1/2 ar(ARC)
{2} ar (RQC)=3/8 ar(ABC)
3) ar (pBQ) = ar(ARC)
Prove that area of a rhombus is half the product of its diagonals.
Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that
[Hint: From A and C, draw perpendiculars to BD]
1) ABCD is a paralellogram. X and Y are mid points of BC and CD respectively.Prove that area (AXY) = 3/8 area(paralellogram ABCD)
2) In a triangle ABC P and Q are respectively the mid points of AB and BC and R is the mid point of AP. Prove that:
1) area(PRQ) =1/2 area(ARC)
2) area(RQC) = 3/8 area(ABC)
3) area(PBQ) = area(ARC)
ABCD is a trapezium in which AB is parallel to DC. DC=30 cm. and AB=50cm. if X and Y are respectively the mid points of AD and BC, prove that (Nine times the area of DCYX= seven times the area of XYBA.)
if the medians of a triangle ABC intersect at G show that ar ( AGB ) = ar(AGC)=ar(BGC)=1/3 ar(ABC).
prove that two triangles having the same base (or equal bases) and equal areas lie between the same parallels.
prove that median divides triangle into two equal parts
The median BE and CF of a triangle ABC intersect at G. prove that area of triangle-GBC = area of quadrilateral AFGE.
Diagonals AC and BD of trapezium ABCD with AB||DC intersect each other at O.
prove that ar(AOD) = ar (BOC)?
prove that the diagonals of a parallelogram divides into four triangle of an equal area
ABCD is a parallelogram in which BC is produced to E such that CE = BC(Fig. 9.17). AE intersects CD at F.If ar (DFB) = 3 cm2, find the area of the parallelogram ABCD.
in a triangle ABC,E is the midpoint of median AD. Show that area of BED = 1/4 area of ABC
The diagonals of a parallelogram ABCD intersect at point O. Through O, a line is drawn to intersect
AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal areas.
P and Q are respectively the mid points of side AB and BC of a triangle ABC and R is the mid point of AP show that,
{1} ar(PQR)= 1/2 ar(ARC)
{2} ar (RQC)=3/8 ar(ABC)
3) ar (pBQ) = ar(ARC)
Prove that area of a rhombus is half the product of its diagonals.
Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that
[Hint: From A and C, draw perpendiculars to BD]