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Chharishma.r.nayaka
Subject: Maths
, asked on 27/10/17
Plz expain how to solve dis...
V
n
∈
N
1
)
sin
(
n
x
)
<
sin
x
2
)
sin
(
n
x
)
<
n
sin
x
3
)
sin
(
n
x
)
≤
n
sin
x
4
)
sin
(
n
x
)
≤
sin
n
Answer
1
Chharishma.r.nayaka
Subject: Maths
, asked on 27/10/17
Plz expain how to solve dis...
∀
n
∈
N
,
1
+
2
x
+
3
x
2
+
.
.
.
.
.
.
.
+
n
.
x
n
-
1
=
(
x
∈
R
,
X
≠
1
)
1
)
1
-
(
n
+
1
)
x
n
+
n
.
x
n
+
1
1
-
x
2
2
)
n
+
1
x
n
1
-
x
2
3
)
1
-
(
n
+
1
)
x
n
+
n
.
x
n
+
1
1
+
x
2
4
)
n
-
1
x
n
1
+
x
2
Answer
1
Chharishma.r.nayaka
Subject: Maths
, asked on 26/10/17
∀
n
∈
N
,
1
+
2
x
+
3
x
2
+
.
.
.
.
+
n
.
x
n
-
1
=
(
x
∈
R
,
x
≠
1
)
1
)
1
-
(
n
+
1
)
x
n
+
n
.
x
n
+
1
(
1
-
x
)
2
2
)
(
n
+
1
)
x
n
(
1
-
x
)
2
3
)
1
-
(
n
+
1
)
x
n
+
n
.
x
n
+
1
(
1
+
x
)
2
4
)
(
n
-
1
)
x
n
(
1
+
x
)
2
Answer
1
Chharishma.r.nayaka
Subject: Maths
, asked on 26/10/17
F
o
r
a
n
y
n
∈
N
,
t
h
e
v
a
l
u
e
o
f
t
h
e
e
x
p
r
e
s
s
i
o
n
2
+
2
+
2
+
.
.
.
n
t
i
m
e
s
i
s
1
)
2
cos
π
2
n
+
1
2
)
2
sin
π
2
n
+
1
3
)
2
cos
2
n
+
1
π
4
)
2
cos
(
2
n
π
)
Answer
1
Chharishma.r.nayaka
Subject: Maths
, asked on 26/10/17
5
.
∑
k
=
1
n
k
(
1
+
1
n
)
k
-
1
(
i
)
n
(
n
-
1
)
(
i
i
)
n
(
n
+
1
)
(
i
i
i
)
n
2
(
i
v
)
(
n
+
1
)
2
Answer
1
Chharishma.r.nayaka
Subject: Maths
, asked on 26/10/17
Q.
∀
n
Σ
N
,
|Sin (n x)| < |Sin x|
|Sin (n x)|< n |Sin x|
|Sin (n x)|
≤
n |Sin x|
sin (n x)
≤
Sin n
Answer
1
Chharishma.r.nayaka
Subject: Maths
, asked on 25/10/17
For any integer n
≥
1, then
∑
k
=
1
n
k
(
k
+
2
)
is equal to?
Answer
1
Chharishma.r.nayaka
Subject: Maths
, asked on 25/10/17
2
.
I
f
a
x
=
1
k
(
k
+
1
)
f
o
r
k
=
1
,
2
,
3
,
.
.
.
.
n
,
t
h
e
n
f
i
n
d
t
h
e
v
a
l
u
e
o
f
∑
k
=
1
n
a
x
2
?
Answer
1
Mayank Kumar
Subject: Maths
, asked on 25/10/17
3 ^n is divided by 8 the remainder is always 1
Answer
1
Janardhan Shiva
Subject: Maths
, asked on 1/10/17
Is there any thumb rule by which divisibility of a cubic polynomial p(x) by a linear polynomial( x+1) or x-1 can be checked ? i remember reading something about sum of even power terms being equal to sum of odd power terms...
Answer
1
Kartik Agarwal
Subject: Maths
, asked on 27/9/17
Q.23. Prove by induction that
n
5
5
+
n
3
3
+
7
n
15
is a natural number for all n
∈
N.
Answer
1
Shubhrajyoti Ghosh
Subject: Maths
, asked on 20/9/17
Dear Expert,
Please explain how we can get,
7/9[10+100+1000+...(m+1) term-(1+1+1...m+1 term...+1]
=7/9[{10(10m+1-1)/9}-m+1]
Answer
1
Vritti Gianchandani
Subject: Maths
, asked on 18/9/17
DearSir/Madam/Friend The price of 2 notebooks and 3 textbooks is Rs.120,but a notebook costs Rs.10 more than the textbook.Find the cost of both; the notebook and textbook? Need Urgently for tommorow's SA1 EXAM
Answer
2
Aditya Dwivedi
Subject: Maths
, asked on 16/9/17
Please explain how
2
.
2
k
>
2
k
i.e.
2
k
+
1
>
2
k
=
k
+
k
>
k
+
1
.
Answer
1
Erw Trjerth
Subject: Maths
, asked on 15/9/17
Plz answer the 17 question
Answer
1
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What are you looking for?
Q.
Please explain how we can get,
7/9[10+100+1000+...(m+1) term-(1+1+1...m+1 term...+1]
=7/9[{10(10m+1-1)/9}-m+1]
i.e.