a ball is given a velocity 2m/s and is subjected to acceleration 4m/s² perpendicular to the initial motion. What is its displacement after 2 seconds?

Dear Student,

Please find below the solution to the asked query:

Let the particle is having velocity in x - direction and acceleration is in y - direction. Then the object will move with uniform velocity in x - direction and with uniform acceleration in y - direction. Therefore,

Displacement along  x - direction is,

$x=ut=2\times 2=4 m$

Displacement along  y - direction is,

$y=\frac{1}{2}a{t}^2=\frac{1}{2}\times 4\times 2^2=8 m$
Therefore, the total displacement is,

$S=\sqrt{x^2+y^2}=\sqrt{4^2+8^2} =\sqrt{16+64}=\sqrt{80}\approx 9 m$

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