A car X is right now on a cross road and moving towards north at 40kmph,Another car Y which is at 5km west of the cross road right now is approaching the crossing at 40kmph.Their shortest distance of approach will be ?
ans-5/root2
plz explain

Dear Student,
Please find below the solution to the asked query:
 tanθ=v1v2θ=tan-14040  =tan-11  =450For shortest distance method:Distance, d=xsinθ                     =5 sin45                      =5×12                      =52 km
Hope this information will clear your doubts about Shortest distance method.
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