A particle is projected with velocity 50 m/s at an angle 60o with the horizontal from the ground. The time after which the velocity will make an angle 45o with the horizontal is ( a) 2.5 s ( b)1.83s ( c)2.37s ( d)3.72s Share with your friends Share 0 Ved Prakash Lakhera answered this According to the given question u cosθ=v cosϕi. e. 50 cos60°=v cos45°or v=50 cos60° cos45°=50×1×22×1=252 m/sLet after time t v=252 m/s is the velocity acquired.So v sin45°=u sin60°-gti. e. 252×12=50×32-9.8tor 25=253 -9.8tor t=253-19.8=25×0.7329.8=1.83sTherefore the correct answer is option b1.83s. 4 View Full Answer Adarsh Saini answered this FGTI 0