A particle is projected with velocity 50 m/s at an angle 60o with the horizontal from the ground. The time after which the velocity will make an angle 45o with the horizontal is
( a) 2.5 s
( b)1.83s
( c)2.37s
( d)3.72s

According to the given question         u cosθ=v cosϕi. e.      50 cos60°=v cos45°or         v=50 cos60° cos45°=50×1×22×1=252 m/sLet after time t v=252 m/s is the velocity acquired.So              v sin45°=u sin60°-gti. e.               252×12=50×32-9.8tor                  25=253 -9.8tor                  t=253-19.8=25×0.7329.8=1.83sTherefore the correct answer is option b1.83s.

  • 4
FGTI
  • 0
What are you looking for?