A particle is thrown with initial speed of 5m/s horizontally under gravity. The distance covered by the particle in vertical downward direction, when its horizontal displacement is 5m.

1. 10m

2.5m

3.2.5m

4.12.5m

Question

A particle is thrown with initial speed of 5m/s horizontally
under gravity The distance covered by the particle in vertical
downward direction, when its horizontal displacement is 5m
1 10m
2 5m
3 2 5m
4 12 5m

Neha Gupta · Accepted Answer

Initial velocity in horizontal doirection is ux = 5 m/sDistance travelled is horizontal direction :sx= uxt + 12axt2acceleration in horizontal direction = 05 = 5×tt = 1 sinitial velocity in vertical direction uy = 0distance travelled in vertical direction :sy = uyt +12ayt2acceleration in y direction is equal to the acceleration due to gravitysy = 0 + 12×10×1×1= 5 m

Hence option (2) is correct

A particle is thrown with initial speed of 5m/s horizontally under gravity. The distance covered by the particle in vertical downward direction, when its horizontal displacement is 5m. 1. 10m 2.5m 3.2.5m 4.12.5m

A particle is thrown with initial speed of 5m/s horizontally under gravity. The distance covered by the particle in vertical downward direction, when its horizontal displacement is 5m.

1. 10m

2.5m

3.2.5m

4.12.5m