a particle starts from rest at A and moves with uniform acceleration a m/s^2 in a straight line .after 1/a seconds a second particle starts from A and moves wuth uniform velocity u in the same line and direction.if u>2m/s then during the entire motion the second particle remains ahead of the first particle for a duration

Lets say that they meet after t sec of particle 1's start. 
The distance travelled by particle 1=distance travelled by particle 2
12at2=u(t-1a)at2=2ut-2uaat2-2ut+2ua=0t=u±u2-2ua
Now t has two values. For The time in between these two solutions, particle 2 remains ahead of particle 1. The time duration is
Δt=u+u2-2ua-u-u2-2ua=2u2-2ua

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