A projectile projected with an initial velocity of 30m/s and angle of projection 100
covers a particular horizontal range. Suggest another angle of projection that covers 
the same horizontal range if the initial velocity remains same.   
 

Dear Student, 

The angle at which the Horizontal Range remains same is 90 - θ
As per the question angle of projection exceeds 90. So the angle given must be 2θ which makes θ = 50
Hence, 
θ2 = 90 - 50θ2 = 40
Regards.

  • 1
What are you looking for?