a projectile thrown from a horizontal plane reaches back the plane after covering distance of 40m .if the horizontal velocity of projectile is 10ms .thenwhat is its initial vertical velocity? take g=10ms
Dear Student,
Horizontal range(R) is 40m and horizontal velocity(uh) is 10m/s.
So we know that
R = uh T
T = 4sec
For finding the vertacal velocity we use newton's 1st equation of motion
At maximum point of projectile the final velocity must be zero.
v = uv - gT' where T' = T/2= 2sec
uv = 20m/s
Regards
Manoj Singh
Horizontal range(R) is 40m and horizontal velocity(uh) is 10m/s.
So we know that
R = uh T
T = 4sec
For finding the vertacal velocity we use newton's 1st equation of motion
At maximum point of projectile the final velocity must be zero.
v = uv - gT' where T' = T/2= 2sec
uv = 20m/s
Regards
Manoj Singh