a shell is fired at an angle of 60 degree to the horizontal direction with the velocity of 392 m/s . find the time of flight , horizontal range , maximum height attained.

Time of flight, T=2usinθg=2×392×sin 6009.8=2×392×32×9.8=69.3 secHorizontal range, R=u2sin 6009.8=392×392×32×9.8=13579.27 mMaximum height, H=u2sin 2θ2×9.8=392×392×34×2×9.8=5880 m

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