a shell is fired with a speed of 30m/s at an angle of 37 degree with the horizontal after 1 sec shell is moving with qn angle theta degree calculate theta given sin 37 is 3/5??? please answer quickly???

Let us take two components of velocity 1> horizontal = 30cos37^​0 =   30 x 0.8 = 24m/s   and 2> vertical = 30sin37⁰ = 18m/s
and this is a projectile motion in which velocity alng horizontal is not changes at nay time it is 24 m/s. but vertical velocity decrease with time
now velocity of bullet after 1 second along vertical direction
v = u+at                                                                  
v = 18 +(-10) x 1                 ( a = -g)
v  = 18 -10  = 8 m/s       ..........1>
                             now velocity along horizontal is always 24 m/s
$$\begin{gathered} \tan \theta = \frac{velocity along vertical \left(v_y\right)}{velocity along horizontal \left(v_x\right)} = \frac{8}{24} =\frac{1}{3} \\ \theta = {\tan }^{-}\left(\frac{1}{3}\right) \end{gathered}$$ m/s