Find wether the vectors 2i+3j+4k and 4i+6j+8k are parallel or not. Share with your friends Share 2 Dinesh Pandey answered this Dear Student, A→=2i^+3j^+4k^B→=4i^+6j^+8k^cosθ=A→.B→A→B→cosθ=2i^+3j^+4k^4i^+6j^+8k^4+9+1616+36+64cosθ=8+18+3229116cosθ=5822929=5858=1θ=0°Hence, vector A→ & B→ are parallel. 6 View Full Answer Meethi answered this If they are parallel then their dot product/ magnitude must be one 8+18+32 / root 29. 3364 =cos A As not equal to 1 so not parallel as cos 0 must be 1 1
